- 5
^{99} - 3
^{99} - 2
^{99} - 6
^{99}

Option 1 : 5^{99}

Using binomial expansion:

(3 + 2x)99 = a0x0 + a1x1 + a2x2 + a3x3 + ……. + a15x15

After putting x = 1

(3 + 2)99 = a0 + a1 + a2 + a3 + …… + a15

599 = a0 + a1 + a2 + a3 + …… + a15

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