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GATE EE 2015 Official Paper: Shift 2

CT 1: Ratio and Proportion

2672

10 Questions
16 Marks
30 Mins

__Concept__

Under steady state load torque will be equal to The developed torque by the motor.

__Explanation__

Given,

no load speed (ω0) = 200 rad/sec

Rated torque (T_{r}) = 500 Nm

Rated Speed (ωr) = 180 rad/sec

Load torque (TL) = 2.78 ω_{r}

using equation of straight line

Developed torque can be expressed as,

\(T=\frac{200-ω_r}{20}\times500\)

At steady state,

load torque = developed torque

⇒ T_{L} = T

⇒ 2.78 ω_{r} = \(\frac{200-ω_r}{20}\times500\)

⇒ ω_{r} = 180 rad/sec

Therefore, steady state speed is 180 rad/sec